思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
算力市场的格局，正加速滑向惨烈的“军备竞赛”。
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Credit: Paramount
Crash regression for state machine conflicts: A test specifically checks that calling byobRequest.respond() after enqueue() doesn't crash the runtime. This sequence creates a conflict in the internal state machine — the enqueue() fulfills the pending read and should invalidate the byobRequest, but implementations must gracefully handle the subsequent respond() rather than corrupting memory in order to cover the very likely possibility that developers are not using the complex API correctly.